Question

z1=26+5i
z2=3-2i

z1+z2
z1-z2
z1.z2

Answer 1

$z_1=26+5i$

$z_2=3-2i$

$z_1+z_2=(26+5i)+(3-2i)=(26+3)+(5-2)i=29+3i$.

$z_1-z_2=(26+5i)-(3-2i)=(26-3)+(5+2)i=23+7i$

$z_1z_2=(26+5i)(3-2i)=78-52i+15i-10i^2=78-37i+10=88-37i$

Answer 2

z1 + z2 =26+5i + 3-2i = 29 +3i

z1-z2 = 26+5i - (3-2i) = 26 + 5i - 3 + 2i = 23 +7i

z1.z2 = (26+5i)(3-2i) = 78 - 52i + 15i - 10i² = 88 - 37i