Question

Sabendo que log 2= o,301 e log 3= 0,477, calcule:
a) Log 6
b) Log 5
c) Log 2,5

Answer 1

Log6:2x0,477 =0,954
Log5:0,301+0,477=0,778
Log2,5:Log2/2/2 para descobrir 0,5 do valor=0,075,25
0,301+0,75,25=0,376,25

Answer 2

log 6 = log 2x3 = log2 + log3 = 0,301+0,477= 0,778
log 5 = log 10/2 = log 10 - log 2 = 1 - 0,301= 0,699 ,pois, log 10= 1
log 2,5 = log 25/10 = log 25 - log10 = 2 log 5 - 1= 2x0,699 - 1= 1,398 - 1= 0,398