Question

Sendo
S = (X + √7) . (X - √7),
P = (X - 3)² - 12
Q = (X+5) (X-2) (X-1)
Determine,
Q - (S+P)

Answer 1

S = (X + √7) . (X - √7)
S = x² - x√7 + x√7 - 7
S = x² - 7

P = (X - 3)² - 12
P = x² - 3x -3x + 9 -12
P = x² - 6x - 3

Q = (X+5) (X-2) (X-1)
Q = x² -2x +5x -10 (x-1)
Q = x3 - x² -2x² + 2x + 5x² -5x -10x + 10
Q = x3 + 2x² - 3x + 10

Q - (S+P)
x3 + 2x² -3x + 10 - (x² - 7 + x² - 6x - 3)
x3 + 2x² -3x + 10 - (2x² -6x -10)
x3 + 2x² -3x + 10 - 2x² + 6x + 10
x3 + 0x² + 3x + 20
x3 + 3x + 20