Question

a²+2ab+b² / a²-b² para a=5 e b=3

Answer 1

Substituindo, temos: (5)² + 2(5)(3) + (3)² / (5)² - (3)² = 25 + 30 + 9 / 25 - 9 = 64 / 16 = 4

Answer 2

$\frac{a^2+2ab+b^2}{a^2-b^2}= \frac{(a+b)^2}{(a+b)(a-b)}=$$\frac{a+b}{a-b}$

$\frac{a+b}{a-b}---->a=5 -----b=3$

$\frac{5+3}{5-3}= \frac{8}{2}=4$