Question

Determine as coordenadas do vértice da função f(x) = (2-x) (x+3)

Answer 1

vamos lá...

f(x)=(2-x)(x+3)

(2-x)(x+3)=0

2x+6-x²-3x=0

-x² -x+6=0   ×(-1)

x² +x -6=0

a=1
b=1
c=-6

Δ=b²-4ac
Δ=1²-4(1)(-6)
Δ=1+24
Δ=25

$Xv=- \frac{b}{2a} =- \frac{1}{2} \\ \\ Yv=- \frac{\triangle}{4a} =- \frac{25}{4} \\ \\ V(- \frac{1}{2} ,- \frac{25}{4} )$