Question

calcule as raizes da equação 3x.(x + 2) + (x - 1)² = x + 1

Answer 1

3x ( x + 2 ) + ( x  - 1)² = x + 1
3x² + 6x + ( x² - 2.x.1 + 1² )  = x + 1 
3x² + 6x + x² - 2x + 1 - x - 1 = 0
4x² + 3x = 0
x ( 4x + 3 ) = 0
x = 0  ****

4x + 3 = 0
4x = -3
x = -3/4 **** resposta

Answer 2

$3x*(x + 2) + (x - 1)^2 = x + 1 \\ \\ 3x*(x + 2) + (x^2-2x+1) = x + 1 \\ \\ 3x^2 + 6x + x^2-2x+1 = x + 1 \\ \\ 3x^2 + 6x + x^2-2x+1 -x - 1= 0 \\ \\ 4x^2 + 3x = 0 \\ \\ x( 4x+3) = 0 \\ \\ x_1= 0\qquad\qquad 4x+3= 0\\ \\ x_1= 0\qquad\qquad x_2= -\frac{3}{4}$