Question

$3 x^{2} +2x-5=0$

Answer 1

Olá

Resolvendo temos :

3x² + 2x - 5 = 0

x = -2 ± √2²-4*3*(-5) / 2*3

x = -2 ± √4+60 / 6

x = -2 ± √64 / 6

x = -2 ± 8 / 6

Logo concluímos que 

x1 = 1
x2 = -5/3

Att

Answer 2

Olá, bom dia ☺

Resolução:

3x²+2x-5=0

Coeficientes:

a=3
b=2
c=-5

Valor do discriminante:

$\Delta=b^2-4.a.c \\ \Delta=2^2-4.3.(-5) \\ \Delta=4+60 \\ \Delta=64$

Valores de x:

$\\x= \dfrac{-b\pm \sqrt{\Delta} }{2.a} \\ \\ x= \dfrac{-2\pm8}{6} \\ \\x'= \dfrac{-2+8}{6}=1 \\ \\ x''= \dfrac{-2-8}{6}= -\dfrac{5}{3}$

S={1,-5/3}

Bons estudos :)