Question

aplicando a formula a)A5,3 b)A8,5 c)A9,7 alguém pode me ajudar.

Answer 1

$\boxed{A_{n,p} = \frac{n!}{(n-p)!}}$

a) A5,3

$A_{5,3} = \frac{5!}{(5-3)!}\\ \\ A_{5,3} = \frac{5!}{2!}\\ \\ \boxed{A_{5,3}=60}$

b) A8,5

$A_{8,5} = \frac{8!}{(8-5)!}\\ \\ A_{8,5} = \frac{8!}{3!}\\ \\ \boxed{A_{8,5}=6720}$

c) A9,7

$A_{9,7} = \frac{9!}{(9-7)!}\\ \\ A_{9,7} = \frac{9!}{2!}\\ \\ \boxed{A_{9,7} = 181440}$