Question

letra a x+5y=11
3x-y-5=0

letra b x+3y =-4
2(x-3)=y PFVR ME RESPONDAMMM ME AJUDEM

Answer 1

A) $\left \{ {{x+5y=11} \atop {3x-y-5=0}} \right.$
x+5y=11
x= 11-5y

3x-y-5=0
3(11-5y)-y-5=0
33-15y-y-5=0
16y= 28
y= $\frac{28}{16} = \frac{7}{4}$

x= 11-5y
x= 11 -5$\frac{7}{4}$
x= 11 -$\frac{-35}{4}$
x= $\frac{44-35}{4} = \frac{9}{4}$

B)$\left \{ {{x+3y =-4} \atop {2(x-3)=y}} \right.$
x+3y= -4
x= -3y -4

2(x-3)= y
2(-3y-4-3)= y
-6y -8 -6= y
-6y -y= 6+8
-7y= 14 (-1)
7y= -14
y= $\frac{-14}{7} = -2$

x= -3y-4
x= -3(-2)-4
x= 6-4
x= 2

Answer 2

Boa noite Zabrin

a)

x + 5y = 11,
3x - y = 5 

x + 5y = 11
15x - 5y = 25
16x = 36
x = 36/16 = 9/4 

9/4 + 5y = 44/4
5y = 35/4
y = 35/20 = 7/4 

S = (9/4, 7/4)

b)

x + 3y = -4 ,
2*(x - 3) = y

x + 3y = -4
2x - y = 6

x + 3y = -4
6x - 3y = 18
7x = 14
x = 2

2 + 3y = -4
3y = -6
y = -2

S = (2, -2)