Question

Encontre o valor numérico

Answer 1

$\dfrac{4}{3}. x^{2}.y - \dfrac {3}{8}.x^{2}.y + \dfrac {4}{9}.x^{2}.y - \dfrac {1}{4}.x^{2}.y$

x= -1
y = 2

$\dfrac{4}{3}. (-1)^{2}.(2) - \dfrac {3}{8}.(-1)^{2}.(2) + \dfrac {4}{9}.(-1)^{2}.(2) - \dfrac {1}{4}.(-1)^{2}.(2)$

$\dfrac{4}{3}.2 - \dfrac {3}{8}.2 + \dfrac {4}{9}.2- \dfrac {1}{4}.2$

$\dfrac{8}{3} - \dfrac {6}{8} + \dfrac {8}{9} - \dfrac {2}{4}$

$\dfrac{8}{3} - \dfrac {3}{4}+ \dfrac {8}{9}- \dfrac {1}{2}$

mmc entre 2, 3, 4, 9 = 36

$\dfrac{(8.12) - (3.9) + (8.4) - 18}{36}$

$\dfrac{96 - 27 + 32 - 18}{36}$

$\dfrac{83}{36}$