Question

dada a função por f (x)=3x+1, calcule f (235)-f (129) sobre 106

Answer 1

f (235) =3*235+1
f(129) = 3*129 +1

f (235)-f (129) =3*235+1 - 3*129 -1

=3*(235-129) =3*106 =318

Answer 2

f (x)=3x+1, calcule f (235)-f (129) sobre 106


f(235)= 3(235) + 1 = 705+1= 706

f(129) = 3(129) + 1 = 387+1= 388

f (235)-f (129) = 706 - 388 =  318  ==> 3
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