Question

(2x-5)^2+(x-2) (+2) = x+(x+7)^2

Answer 1

(2x - 5)² + (x - 2) (+2) = x + ( x + 7)²
4x² - 20x + 25 + 2x- 4 = x + x² + 14x + 49
4x² - 18x + 21 = 15x + x² + 49
4x² - 18x + 21 - 15x - x² - 49 = 0
3x² - 33 - 28 = 0
x = -(-33) ± √(-33)²-4*3(-28)
/ 2*3
x= 33± √1089+336
6
x=33 ± √1425
6
x= 33± 5 √57
6
X1= 33 + 5√57
6

x2= 33 -5√57
6
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