Question

Simplifique as frações admitindo que os denominadores sejam diferentes de zero

a) (x² - 4) / (x – 2) =
b) (a² - 9) / 5(a + 3) =
c) (4x² - y²) / ( 2x – y) =
d) (a + b)⁵ / (a + b)² =
e) ( a – b)² / ( a² - b²) =
f) (x + y)² / ( x² - y²) =
g) (x² - 2x + 1) / (x² - 1) =
h) ( a + 1) / (a² + 2 a + 1) =
i) (x² + 6x + 9) / (2x + 6) =

Answer 1

a) (x+2).(x-2)/(x-2) = (x+2)

b) (a+3).(a-3)/5(a+3) = (a-3)/5

c) (2x-y).(2x+y)/(2x-y) = (2x+y)

d) (a+b)² . (a+b)² . (a+b)/(a+b)² = (a+b)³

e) (a-b) . (a-b)/(a-b) . (a+b) = (a-b)/(a+b)

f) (x+y) . (x+y)/(x-y) . (x+y) = (x+y)/(x-y)

g) (x-1) . (x-1)/(x-1) . (x+1) = (x-1)/(x+1)

h) (a+1)/(a+1) . (a+1) = 1/(a+1)

i) (x+3) . (x+3)/2(x+3) = (x+3)/2