Question

(x+1)²=4x+4 pfvrrr urgenteee

Answer 1

Olá!


$(x+1)^2=4x+4\\\\(x+1)(x+1)=4x+4\\\\x^2+x+x+1^2=4x+4\\\\x^2+2x+1=4x+4\\\\x^2+2x-4x+1-4=0\\\\x^2-2x-3=0\\\\x=\dfrac{-(-2)\pm\sqrt{(-2)^2-4.(1).(-3)}}{2.(1)}\\\\x=\dfrac{2\pm\sqrt{16}}{2}\\\\x=\dfrac{2\pm4}{2}\left\langle\begin{array}{lll}x=3\\\\x=-1\end{array}\right\\\\\\\boxed{\boxed{S=\{-1,\,3\}}}$



Bons estudos!