Question

utilizando o teorema de pitagoras ,determine o valor de x no triangulo retangulo: cat a:3x cat b:4x hip:20.... preciso hj...pr favor?

Answer 1

$20^{2}=(3x)^{2}+(4x)^{2}$

$400 = 9x^{2}+16x^{2}$

$400 = 25x^{2}$

$x^{2} = \frac{400}{25}$

$x^{2} = \frac{80}{5}$

$x^{2} = 16$

$x= \sqrt{16}$

$x= 4$

Resposta: X vale 4

Answer 2

20^2 = (4x)^2 + (3x)^2
400=16x^2 + 9x^2
400=25x^2
x^2=400/25
x^2=16
x= 4 ou -4