Question

x²-5x=104 formula de bhaskara

Answer 1

x²-=104
x²-5x+104
Δ=b²-4ac
=(-5)²-4*1*(-104)
=25+416
=440
x= -b⁺₋√Δ/2a
=-(-5)⁺₋√440/2*1
x¹= 5-20,9/2=-15,9/2=-7,95

x²=5+20,9/2=25,9/2=12,95
 x={-7,95 e 12,95 }