Question

As raizes reais da equaçao 1,5x^2 + 0,1x = 0,6 sao:a) 2/5 e 1b) 3/5 e 2/3c) - 3/5 e - 2/5d) - 3/5 e 2/3e) 3/5 e -2/3

Answer 1

a=1,5 = 3/2
b=0,1 = 1/10
c=-0,6 = -6/10

delta=(1/10)²-4*(3/2)*(-6/10)
delta=1/100+72/20 = (1+5*72)/100 = 361/100

raiz(delta)=raiz(361/100)=19/10

x'=(-1/10+19/10)/2*(3/2) = (18/10)*(1/3)=18/30=3/5
x"=(-1/10-19/10)/2*(3/2)= -19/10*1/3=-19/30