Question

determine o valor de x em:

log 125√5=x

Answer 1

$\boxed{log_a~b=x\rightarrow a^x=b}$

Logo, temos que:

$log_{125}~\sqrt{5} = x\\ \\ 125^x = \sqrt{5}\\ \\ 5^{3x} = 5^{\frac{1}{2}}\\ \\ 3x=\frac{1}{2}\\ \\ x=\frac{1}{2\cdot 3}\\ \\ \boxed{x=\frac{1}{6}}$