Question

B= (aij)3×3 aij= 3i+2j-5

Answer 1

B=(aij) 3×3.

[a11 a12 a13]
[a21 a22 a23]
[a31 a32 a33]

aij= 3i+2j-5
a11= 3.1+2.1-5=0
a12= 3.1+2.2-5= 2
a13= 3.1+2.3-5= 4
a21= 3.2+2.1-5= 3
a22= 3.2+2.2-5= 5
a23= 3.2+2.3-5= 7
a31= 3.3+2.1-5= 6
a32= 3.3+2.2-5= 8
a33= 3.3+2.3-5= 10

[ 0 2 4 ]
[ 3 5 7 ]
[ 6 8 10]