Question

resolva as eguacoes a) (x+1)^2-x^2=17 b) x (x+5)=(x+1)^2 +26 C) (x-4) ^2=x^2-40 Me ajudem por favor!

Answer 1

a) (x+1)^2 -x^2=17
(x+1). (x+1)-x^2=17
(x^2 +1x+ 1x+1)-x^2=17
(x^2+2x +1)-x^2=17
x^2 - x^2 +2x= 17-1
2x =16
x=16/2
x=8

b) x (x+5)=(x+1)^2 +26
x^2 + 5x = x^2+ 2x +1 +26
x^2 -x^2 +5x -2x=26 +1
3x=27
x=27/3
x=9


C) (x-4) ^2=x^2-40
(x-4). (x-4)=x^2 -40
(x^2 -4x -4x +16)=x ^2 -40

x^2 -8x +16=x^2 -40
x^2 -x^2 -8x =40+16
-8x=56
x=56/-8
x=-7


espero ter ajudado