Question

determine a funcao quadratica f(x)=ax^2+bx+c sabendo que f(0)=5; f(-1)=-3 e f(2)=3

Answer 1

f(0)=c
c=5

f(-1)= a-b+5
-3= a-b+5
a-b= -8

f(2)=4a+2b+5
3= 4a+2b+5
4a+2b=-2

a-b=-8 (2)
4a+2b=-2

2a-2b=-16
4a+2b=-2
=========
6a=-18
a=-3

a-b=-8
-3-b=-8
-b=-5
b=5

f(x)=-3x²+5x+5