Question

Quantos termos formam a p.g (3,6...,768)?

Answer 1

a1 = 3
r = 6 / 3 = 2

an = a1 * r ^(n - 1)
768 = 3 * 2 ^(n - 1)
768 / 3 = 2 ^(n - 1)
256 = 2^(n - 1)
2^8 = 2^(n - 1)
8 = n-1
n = 8 + 1
n = 9

espero ter ajudado