Question

Sendo P(x)=x⁴-2x²+5x+1 , calcule :

A) P(3)  
B) P( -1)
C) P(-2)
D) P (0)

Answer 1

é só jogar o valor de dentro do parênteses no x

$P(x)=x^4-2x^2+5x+1$

$P(3)=3^4-2.3^2+5.3+1$

$P(3)=81-18+15+1$

$\boxed{\boxed{P(3)=79}}$

$P(x)=x^4-2x^2+5x+1$

$P(-1)=(-1)^4-2.(-1)^2+5.(-1)+1$

$P(-1)=1-2-5+1$

$\boxed{\boxed{P(-1)=-5}}$

$P(x)=x^4-2x^2+5x+1$

$P(-2)=(-2)^4-2.(-2)^2+5.(-2)+1$

$P(-2)=16-8-10+1$

$\boxed{\boxed{P(-2)=-1}}$

$P(x)=x^4-2x^2+5x+1$

$P(0)=0^4-2.0^2+5.0+1$

$\boxed{\boxed{P(0)=1}}$