• Matéria: Matemática
  • Autor: ysayaralu
  • Perguntado 8 anos atrás

mmc15e25 mmc 18e21 mdc7e21 mdc1050

Respostas

respondido por: marmon
0
\centering 
\begin{tabular}{rr|c|c} 
& & MMC & MDC \\ 
18,& 21,& 2 & \\
9,& 3, & 3\\
3,& 7,& 3 & \\
1,& 7, & 7 \\
1& 1,&  &  \\

\end{tabular}
$$ \text{MMC}\,\,\ 2 \cdot 3^2 \cdot 7 = 126$$

\centering 
\begin{tabular}{rr|c|c}
& & MMC & MDC \\ 
15,& 25,& 3 & \\
5,& 25, & 5\\
1,& 5,& 5 & \\
1,& 1,&  &  \\

\end{tabular}
$$ \text{MMC}\,\,\ 3 \cdot 5^2 = 75$$

MDC é quando divide todos os numeros ao mesmo tempo

\centering 
\begin{tabular}{rr|c|c}
& & MMC & MDC \\ 
7,& 21,& 3 & \\
7,& 7, & 7 & 7\\
1,& 1,&  &  \\

\end{tabular}\\
\\$$ \text{MMC}\,\,\ 3 \cdot 7 = 21$$
$$ \text{MDC}\,\,\ 7 = 7$$

\centering 
\begin{tabular}{rr|c|c}
& & MMC & MDC \\
10,& 50,& 2 & 2\\
5,& 25,& 5 & 5\\
1,& 5,& 5 & \\
1,& 1,&  &  \\

\end{tabular}\\
$$ \text{MMC}\,\,\ 2 \cdot 5^2 = 50$$
$$ \text{MDC}\,\,\ 2 \cdot 5 = 10$$

Bons estudos
Perguntas similares