Question

•Encontre O Coeficiente E Resolva As Equações Do 2° Grau•

a) x² - 26x + 160

b) 5 + 6x = -x²

Answer 1

a)
$x^{2}$ - 26x + 160 = 0
Coeficientes: a = 1, b = -26, c = 160
Δ = $b^{2} -4ac$
Δ = $(-26^{2}) -4.1.160$
Δ = 676 - 640
Δ = 36

-b+/-$\sqrt$Δ/2.a
26+/-$\sqrt{36}$/2.1
$\frac{26+-6}{2}$
x'= $\frac{26+6}{2}$
x'= $\frac{32}{2}$
x'= 16
x''= $\frac{26-6}{2}$
x''= $\frac{20}{2}$
x'' = 10
S= {( 16,10 )}

b) $5 +6x = -x^{2}$
$x^{2} + 6x +5 = 0$
Coeficientes: a = 1, b = 6, c = 5
Δ = $b^{2} -4ac$
Δ = $( 6^{2}) -4.1.5$
Δ = 36 - 20
Δ = 16

-b+/-$\sqrt$Δ/2.a
-6+/-$\sqrt{16}$/2.1
$\frac{-6+-16}{2}$
x'= $\frac{-6+16}{2}$
x'= $\frac{10}{2}$
x'= 5
x''= $\frac{-6+(-16)}{2}$
x''= $\frac{-22}{2}$
x''= -11
S= {(5,-11)}