Question

Dadas as matrizes m=( mij) sendo mij= 3i+j e n=(nij) sendo nij =4i i2j determine m31-n32

Answer 1

$m_{31}=3\cdot i+j\\ m_{31}=3\cdot 3+1\\ m_{31}=10\\ \\ n_{32}=4 \cdot i^{2} \cdot 2 \cdot j\\ n_{32}=4 \cdot 3^{2} \cdot 2 \cdot 2\\ n_{32}=4 \cdot 9 \cdot 4\\ n_{32}=144\\ \\ m_{31}-n_{32}\\ 10-144= -134$