Question

ME AJUDEEEEEEEEEEEEM CALCULE A SOMA M: M= LOG2 8+LOG3 1/9 +LOG 5 √5

Answer 1

M = log₂ 8 + log₃ 1/9 + log₅ √5

Para:
log₂ 8 = x
2ˣ = 8
2ˣ = 2³
x = 3

Para:
log₃ 1/9 = x
3ˣ = 1/9
3ˣ = 1/ 3²
3ˣ = 3⁻²
x = -2

Para:
log₅ √5 = x
5ˣ = √5
5ˣ = 5^1/2
x = 1/2

Logo
M = 3 + (-2) + 1/2
M = 3 - 2 + 1/2
M = 3/2