Question

X elevado ao quadrado de menos trinta e dois x + duzentos e cinquenta e seis igual a 0

Answer 1

$x^2-32x+256=0$

Coeficientes: a = 1, b = 32 e c = 256.

$\Delta=b^2-4\cdot a\cdot c\\\Delta=(-32)^2-4\cdot1\cdot256\\\Delta=1024-924\\\Delta=100$

$x=\frac{-b+-\sqrt{\Delta}}{2\cdot a}\\\\x=\frac{-(-32)+-\sqrt{100}}{2\cdot1}\\\\x=\frac{32+-10}{2}\\\\x_1=\frac{32+10}{2}=\frac{42}{2}=21\\\\x_2=\frac{32-10}{2}=\frac{22}{2}=11$


Espero ter ajudado.
Bons estudos! :)