Question

x² - yz para x = 1/2 y= 1/3 e z = 1/4

Answer 1

$x^{2} -yz$
$(\frac{1}{2}) - \frac{1}{3}. \frac{1}{4}$
$\frac{1}{4} - \frac{1}{12} [tex] \frac{2-6}{2}$
$\frac{-2}{4}$
$\frac{-2}{1}$
-2

Answer 2

(1/2)^2 - 1/3 * 1/4=
1/4 - 1/12=
3/12 - 1/12=
2/12 ou 1/6