Question

resolva as inequações ( 3x - 1 ) ( -5x - 2 ) ≤0

Answer 1

(3x-1).(-5x-2)≤0 (aplicando a  distributiva teremos)
-15x²- 6x + 5x +2 ≤ 0
-15x² - x + 2 ≤ 0
Δ= -(1)² - 4*(-15)*2
Δ=1 + 120
Δ=121

x1=  $\frac{1 + 11}{-30} = \frac{12}{-30} = \frac{2}{-5}$

x2=  $\frac{1-11}{-30}= \frac{-10}{-30} = \frac{1}{3}$

Lembrando que é ≤ 
S={x∈R/- $\frac{2}{5}$ ≤x ou x≥ $\frac{1}{3}$ }