Question

Calcule $\frac{8-2i}{4-2i}$

Answer 1

$\frac{8-2i}{4-2i}=\frac{8-2i}{4-2i}\cdot\frac{4+2i}{4+2i}=\frac{32+16i-8i-4i^2}{16+8i-8i-4i^2}=\frac{32+8i+4}{16+4}\\\\\frac{36+8i}{20}=\frac{36}{20} + \frac{8}{20}i=\frac{9}{5} + \frac{2}{5}i$