Question

5t²+4t-1=0 equação do 2 grau

Answer 1

$5t^2+4t-1=0\\\\\Delta=(4)^2-4\cdot(5)\cdot(-1)\\\Delta=16+20\\\Delta=36\\\\t=\frac{-(4)\pm\sqrt36}{2\cdot5}\to t=\frac{-4\pm6}{10}\\\\t'=\frac{-4+6}{10}=\frac{2}{10}= \frac{1}{5}\\\\t''=\frac{-4-6}{10}=-1\\\\s=\{\frac{1}{5},-1}\}$