Question

3X quadro+27X+24=0
Na formula de baskara

Answer 1

3 x^{2} +27X+24=0          Simplifica por 3! \\  x^{2} +9x+8=0 \\ Δ= (9)² - 4 (+1) (+8)
Δ = 81 - 32
Δ = 49
X1= - 9 + √49
X1 = -9+7
X1=-2
X2=-9-7
X2=-16

Answer 2

3$X^{2}$ +27X +24 = 0

Δ = $b^{2}$ -4ac
Δ = $27^{2}$ -4 . 3 . 24
Δ = 729 -288
Δ = 441

X = $\frac{-b +- \sqrt{Δ} }{2 . a}$
X = $\frac{-27 +- \sqrt{441} }{2 . 3}$
X = $\frac{-27 +- 21}{6}$

X' = $\frac{-27 +21}{6}$
X' = $\frac{-6}{6}$
X' = -1

X'' = $\frac{-27 -21}{6}$
X'' = $\frac{-48}{6}$
X'' = -8