Question

calcule o valor de x nos triângulos retângulos.

Answer 1

a)
(2X)² = X² + (3*sqrt(3))²
4X² = X² + 9*3;
3X² = 27
X² = 9
X = 3

b)
(X+5)² = 6² + (X+3)²
X² + 2X5 + 5² = 36 + X² + 2X3 + 3²
10X + 25 = 36 + 6X + 9
10X - ¨6X = 36 - 25 + 9
4X = 20
X = 5