Question

Resolva a equação.
20^x=3^x-2

Considere Log 3 = 0,477
Log 2 = 0,301

Answer 1

log20^x = log3^x-2
x log(2.10) = x-2 log 3
x.(0,301 + 1) = (x-2).(0,477)
x.(1,301) = (x-2).(0,477) (multiplica tudo por 1/x)
(1,301) = (x-2)/x .(0,477)
2,727 = (x-2)/x
2,727x = x-2
2,727x - x = -2 (-1)
-2,727x + x = 2
-1,727x = 2
x = 2/-1,727
x= -1,1580