Question

x+1 + x-2 = x-3
2         3         4 

Answer 1

$\frac{x+1}{2}+\frac{x-2}{3}=\frac{x-3}{4}\\\\\frac{x+1}{2}+\frac{x-2}{3}-\frac{x-3}{4}=0$

Como os denominadores são diferentes, temos que fazer o MMC.

MMM (2, 3, 4)

2, 3, 4 l 2
1, 3, 2 l 2
1, 3, 1 l 3
1, 1, 1

2 · 2 · 3 = 12


$\frac{12\div2\cdot(x+1)}{2}+\frac{12\div3\cdot(x-2)}{12}-\frac{12\div4\cdot(x-3)}{12}=0\\\\\frac{6(x+1)}{12}+\frac{4(x-2)}{12}-\frac{3(x-3)}{12}=0\\\\\frac{6x+6}{12}+\frac{4x-8}{12}-\frac{3x-9}{12}=0\\\\\frac{(6x+6)+(4x-8)-(3x-9)}{12}=0\\\\\frac{6x+6+4x-8-3x+9}{12}=0\\\\\frac{7x+7}{12}=0\\\\7x+7=0\cdot12\\7x+7=0\\7x=-7\\x=\frac{-7}{7}\\x=-1$

Resposta: x = -1



Espero ter ajudado.
Bons estudos! :)