Question

Sendo log2 ( x+1 ) = 5 é:

a)S ={31}
b)S ={7, -5}
c)S ={32}
d)S ={7/2}

Answer 1

log (x + 1) = 5
    2

2^5 = x + 1
32 = x + 1
x = 32 - 1
x = 31