Question

h) 6(x+1)-5(x+2)-1=0
i) x-2(x+1)-3(x-1)=0

Answer 1

H) 6 (x + 1) - 5 (x + 2) - 1 = 0
6x + 6 - 5x - 10 - 1 = 0
6x - 5x = +1 + 10 - 6
x = 5

I) x - 2 (x + 1) - 3(x - 1) = 0
x - 2x - 2 - 3x + 3 = 0
x - 2x - 3x = - 3 + 2
- 4x = - 1 (-1)
4x = 1
x = 1/4
x = 0,25

Answer 2

$h ) 6 ( x + 1 ) - 5 ( x + 2 ) - 1 = 0 \\ 6x + 6 - 5x - 10 - 1 = 0 \\ 6x - 5x = - 6 + 10 + 1 \\ x = 5 \\ \\ i) x - 2 ( x + 1 ) - 3 ( x - 1 ) = 0 \\ x - 2x - 2 - 3x + 3 = 0 \\ x - 2x - 3x = 2 - 3 \\ - 4x = - 1 \\ 4x = 1 \\ x = \frac{1}{4} \\ x = 0,25$