Question

se A = lim x tende a 3 (x²-1) e B lim x tende a 9 (x²+2x-1) o valor de A e B é

Answer 1

$A = \lim_{x \to 3} (x^{2} -1) = (3^{2} -1) = (9 - 1) = 8$

$B = \lim_{x \to 9} (x^{2} + 2x - 1) = (9^{2} + 2*9 -1) = (81 + 18 - 1) = 98$