Question

$( x + 3)( x - 2) > 0$

Answer 1

(x+3)(x-2)>0

x²-2x+3x-6>0
x²+x-6>0
Δ=b²-4·a·c
Δ=1²-4·1·-6
Δ=1+24
Δ=25   √25=5

x₁=$\frac{-b+ \sqrt{25} }{2a}$ =
x₁=$\frac{-1+5}{2 ·1}$=
x₁=$\frac{4}{2} = 2$

x₂=$\frac{-1-5}{2} =$
x₂=$\frac{-6}{2} = -3$

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