Question

Resolva a equação do 2° grau:
x² - 5x + 6 = 0

Answer 1

x² - 5x + 6 = 0
Δ= b² - 4ac
Δ= (-5)² - 4.1.6
Δ= 25 - 24
Δ=1 

x= -b +/- √Δ / 2a
x= - (-5) +/- √1 / 2.1
x'= 5 + 1 / 2
x'= 6/2
x'= 3

x''= - (-5) - 1/ 2
x''= 5 - 1/2
x''= 4/2
x''= 2

Bons estudos!

Answer 2

Resolvendo por Bháskara:

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$x^{2} - 5x + 6 = 0$

a=1, b=−5,  c=6

Δ=b²−4ac
Δ=(−5)2−4*(1)*(6)
Δ=25−24
Δ=1

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-(-5) \pm \sqrt{1}}{2*1} \\ \\ \\ x = \dfrac{5 \pm 1}{2} \\ \\ \\ x' = \dfrac{5 + 1}{2} \\ \\ \\ x' = \dfrac{6}{2} \\ \\ \\ x' = 3 \\ \\ \\ \\ x'' = \dfrac{5 - 1}{2} \\ \\ \\ x'' = \dfrac{4}{2} \\ \\ \\ x'' = 2$

S = { 3, 2 }