Question

log2 ( (x2 - 4) / (8x - 16) ) = 0

Answer 1

log2 ( (x²-4) / (8x-16) ) = 0
2 elevado a 0 = (x²-4) / (8x-16)
1 = (x-2)(x+2) / 8(x-2) >>>>>>>>>>> corta-se o (x-2)
1 = (x+2) / 8 >>>>>>>>>>>>>>>>>> multiplica-se o 8 por 1
8 = x+2
8-2 = x
x = 6

Espero ter ajudado :D