Question

Calcule o valor de x usando o teorema de Pitágoras

Answer 1

$A) \\ \\ hip^2 = cat^2 + cat^2 \\ \\ x^2 = 15^2 + 20^2 \\ x^2 = 225 + 400 \\ x^2 = 625 \\ x = \sqrt{625} \\ x = 25m \\ \\ B) \\ \\ 10^2 = 8^2 + x^2 \\ 100 = 64 + x^2 \\ -x^2= 64 - 100 \\ -x^2 = -36 * (-1) \\ x^2 = 36 \\ x = \sqrt{36} \\ x = 6cm$

Answer 2

Teorema de Pitágoras: a² = b² + c²

$a)\:x^{2}=15^{2} +20^{2}\\x^{2} =225+400 \\x^{2} =625 \\\sqrt{x^{2} } =\sqrt{625} \\\boxed{x=25\:m }$

$b)\:10^{2}=x^{2} +8^{2}\\100^{2} =x^{2} +64 \\x^{2} =36 \\\sqrt{x^{2} } =\sqrt{36} \\\boxed{x=6 \:cm}$