Question

$log_{0.5}(0.125)$
Estou com dúvida!

Answer 1

log b = x
    a

$a^x=b$

Então,

$(\frac{1}{2})^x=\frac{1}{8}\\\\\\ (\frac{1}{2})^x=\frac{1^3}{2^3}\\\\\\ (\frac{1}{2})^x=(\frac{1}{2})^3$

Bases iguais, iguala os expoentes.

x = 3

Answer 2

veja....

$\log_{0,5}(0,125)=x \\ \\ (0,5)^x=(0,125) \\ \\ (0,5)^x=(0,5)^3 \\ \\cancela~~as~~bases \\ \\ x=3$