Question

3)Se f(x) = 16^1+1/x, então calcule f(-1) + f(-2) + f(-4)

Answer 1

f(x) = 16 ^(1+1/x)

f(-1)
1 + 1/x
1 + 1/-1
1 -1
0

f(-1) = 16^0 = 1

f(-2)
1 + 1/x
1 + 1/-2
1 - 1/2
1/2

16^(1/2)
√16
4

f(-4)
1 + 1/x
1 + 1/-4
4/4 - 1/4
3/4

16^(5/4)
$\sqrt[4]{ 16^{3} } = \sqrt[4]{4096} = 8$

f(-1) + f(-2) + f(-4)
1 + 4 + 8
13

=)