Question

Qual Lim x tendendo a - infinito (2x²+1/x²-1)

Answer 1

$\lim_{x \to \infty} \dfrac{2x^2+1}{x^2-1}=\\\\\lim_{x \to \infty} \dfrac{2x^2+1}{x^2-1}\cdot\dfrac{\frac{1}{x^2}}{\frac{1}{x^2}}=\\\\\lim_{x \to \infty} \dfrac{2+\frac{1}{x^2}}{1-\frac{1}{x^2}}=\\\\\dfrac{2+0}{1-0}=2$