Question

X= -b+√b²-4.A.C sendo A=2,b=5 e C=2,o Valor ².ª

Answer 1

Δ = $b^{2} - 4.a.c$
Δ = $5^{2} - 4.2.2 = 25 - 16 = 9$
$x = \frac{-2+-3}{4}$
$x' = \frac{-2+3}{4} = \frac{1}{4}$
$x" = \frac{-2-3}{4} = \frac{-6}{4} = \frac{-3}{2}$