• Matéria: Matemática
  • Autor: dbora16dc13d
  • Perguntado 9 anos atrás

Como se resolve o sistema pela regra de cramer 3×+y=4 2x+5y=6

Respostas

respondido por: Niiya
1
\begin{cases}3x+y=4\\2x+5y=6\end{cases}

Achando Δ:

\Delta=\left|\begin{array}{ccc}3~~~1\\2~~~5\end{array}\right|=3\cdot5-1\cdot2=15-2=13

Achando Δx:

\Delta x=\left|\begin{array}{ccc}4~~~1\\6~~~5\end{array}\right|=4\cdot5-1\cdot6=20-6=14

Achando Δy:

\Delta y=\left|\begin{array}{ccc}3~~~4\\2~~~6\end{array}\right|=3\cdot6-4\cdot2=18-8=10
_________________________

Achando x:

x=\dfrac{\Delta x}{\Delta}=\dfrac{14}{13}

Achando y:

y=\dfrac{\Delta y}{\Delta}=\dfrac{10}{13}
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