Question

alguem me ajuda !!!!!!!


1 - calcule o valor de x e y de modo que :
$\left[\begin{array}{ccc}-3&y&\\&&\\x&2&\end{array}\right]$ . $\left[\begin{array}{ccc}&2&\\&&\\&-3&\end{array}\right] = \left[\begin{array}{ccc}&1&\\&&\\&-5&\end{array}\right]$





2- resolva a equação a. x + b = c em que :
$a= \left[\begin{array}{ccc}0&&-1\\&&\\3&&1\end{array}\right] , b= \left[\begin{array}{ccc}&5&\\&&\\&1&\end{array}\right] , c= \left[\begin{array}{ccc}&-3&\\&&\\&0&\end{array}\right]$

Answer 1

$Ola'! \\ \\1) \\ \left[\begin{array}{ccc}-6-3y\\2x-6\\\end{array}\right] = \left[\begin{array}{ccc}1&\\-5&\end{array}\right] \\ \\ -6-3y=1=\ \textgreater \ \boxed{y=- \frac{7}{3}} \\ \\ 2x-6=-5=\ \textgreater \ \boxed{x= \frac{1}{2}} \\ \\ ===================================== \\ 2) \\ ax+b=c \\ \\ \left[\begin{array}{ccc}0&-1\\3&1\end{array}\right] x+ \left[\begin{array}{ccc}5&\\1&\end{array}\right]= \left[\begin{array}{ccc}-3\\0\end{array}\right] \\ \\ -3x= \left[\begin{array}{ccc}-8\\-1&\end{array}\right]$

$\boxed{x= \left[\begin{array}{ccc} \frac{8}{3} \\ \\ \frac{1}{3} \end{array}\right] }$