Question

valor mínimo ou maximo de 4x²+2x-2

Answer 1

'a' > 0, logo temos o valor mínimo

$yv= -\dfrac{\Delta}{4a} \\\\\\yv= -\dfrac{2^2-4 \cdot 4 \cdot (-2)}{4 \cdot 4}\\\\\\yv= -\dfrac{36}{16} \\\\\\yv= - \dfrac{9}{4}$


Forte abraço!